5(a+1)-3(4-a)=6(a-1)+5

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Solution for 5(a+1)-3(4-a)=6(a-1)+5 equation: 



5(a+1)-3(4-a)=6(a-1)+5

We move all terms to the left:

5(a+1)-3(4-a)-(6(a-1)+5)=0

We add all the numbers together, and all the variables

5(a+1)-3(-1a+4)-(6(a-1)+5)=0

We multiply parentheses

5a+3a-(6(a-1)+5)+5-12=0



We calculate terms in parentheses: -(6(a-1)+5), so:

6(a-1)+5

We multiply parentheses

6a-6+5

We add all the numbers together, and all the variables

6a-1

Back to the equation:

-(6a-1)



We add all the numbers together, and all the variables

8a-(6a-1)-7=0

We get rid of parentheses

8a-6a+1-7=0

We add all the numbers together, and all the variables

2a-6=0

We move all terms containing a to the left, all other terms to the right

2a=6

a=6/2

a=3

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