x2-22x-800=0

Solution for x2-22x-800=0 equation:

x2-22x-800=0

We add all the numbers together, and all the variables

x^2-22x-800=0

a = 1; b = -22; c = -800;
Δ = b2-4ac
Δ = -222-4·1·(-800)
Δ = 3684
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3684}=\sqrt{4*921}=\sqrt{4}*\sqrt{921}=2\sqrt{921}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{921}}{2*1}=\frac{22-2\sqrt{921}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{921}}{2*1}=\frac{22+2\sqrt{921}}{2}
$