5(6-2x)+7=4x-(3x-12)

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Solution for 5(6-2x)+7=4x-(3x-12) equation: 



5(6-2x)+7=4x-(3x-12)

We move all terms to the left:

5(6-2x)+7-(4x-(3x-12))=0

We add all the numbers together, and all the variables

5(-2x+6)-(4x-(3x-12))+7=0

We multiply parentheses

-10x-(4x-(3x-12))+30+7=0



We calculate terms in parentheses: -(4x-(3x-12)), so:

4x-(3x-12)

We get rid of parentheses

4x-3x+12

We add all the numbers together, and all the variables

x+12

Back to the equation:

-(x+12)



We add all the numbers together, and all the variables

-10x-(x+12)+37=0

We get rid of parentheses

-10x-x-12+37=0

We add all the numbers together, and all the variables

-11x+25=0

We move all terms containing x to the left, all other terms to the right

-11x=-25

x=-25/-11

x=2+3/11

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