1=2(j+2)+1

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Solution for 1=2(j+2)+1 equation: 



1=2(j+2)+1

We move all terms to the left:

1-(2(j+2)+1)=0



We calculate terms in parentheses: -(2(j+2)+1), so:

2(j+2)+1

We multiply parentheses

2j+4+1

We add all the numbers together, and all the variables

2j+5

Back to the equation:

-(2j+5)



We get rid of parentheses

-2j-5+1=0

We add all the numbers together, and all the variables

-2j-4=0

We move all terms containing j to the left, all other terms to the right

-2j=4

j=4/-2

j=-2

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