-6(v+1)=2v-1+2(5v+5)

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Solution for -6(v+1)=2v-1+2(5v+5) equation: 



-6(v+1)=2v-1+2(5v+5)

We move all terms to the left:

-6(v+1)-(2v-1+2(5v+5))=0

We multiply parentheses

-6v-(2v-1+2(5v+5))-6=0



We calculate terms in parentheses: -(2v-1+2(5v+5)), so:

2v-1+2(5v+5)

determiningTheFunctionDomain
2v+2(5v+5)-1

We multiply parentheses

2v+10v+10-1

We add all the numbers together, and all the variables

12v+9

Back to the equation:

-(12v+9)



We get rid of parentheses

-6v-12v-9-6=0

We add all the numbers together, and all the variables

-18v-15=0

We move all terms containing v to the left, all other terms to the right

-18v=15

v=15/-18

v=-5/6

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