5(4y+1)=30

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Solution for 5(4y+1)=30 equation: 



5(4y+1)=30

We move all terms to the left:

5(4y+1)-(30)=0

We multiply parentheses

20y+5-30=0

We add all the numbers together, and all the variables

20y-25=0

We move all terms containing y to the left, all other terms to the right

20y=25

y=25/20

y=1+1/4

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