3(j-10)+2(j-29)=2

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Solution for 3(j-10)+2(j-29)=2 equation: 



3(j-10)+2(j-29)=2

We move all terms to the left:

3(j-10)+2(j-29)-(2)=0

We multiply parentheses

3j+2j-30-58-2=0

We add all the numbers together, and all the variables

5j-90=0

We move all terms containing j to the left, all other terms to the right

5j=90

j=90/5

j=18

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