(3x+4)=(8x-28)

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Solution for (3x+4)=(8x-28) equation: 



(3x+4)=(8x-28)

We move all terms to the left:

(3x+4)-((8x-28))=0

We get rid of parentheses

3x-((8x-28))+4=0



We calculate terms in parentheses: -((8x-28)), so:

(8x-28)

We get rid of parentheses

8x-28

Back to the equation:

-(8x-28)



We get rid of parentheses

3x-8x+28+4=0

We add all the numbers together, and all the variables

-5x+32=0

We move all terms containing x to the left, all other terms to the right

-5x=-32

x=-32/-5

x=6+2/5

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