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((3x+1)/20)=(1/5)
We move all terms to the left:
((3x+1)/20)-((1/5))=0
We add all the numbers together, and all the variables
((3x+1)/20)-((+1/5))=0
We calculate fractions
3x/()+()/()=0
We add all the numbers together, and all the variables
3x/()+1=0
We multiply all the terms by the denominator
3x+1*()=0
We add all the numbers together, and all the variables
3x=0
x=0/3
x=0
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