5(4y)=10(3y-5)

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Solution for 5(4y)=10(3y-5) equation: 



5(4y)=10(3y-5)

We move all terms to the left:

5(4y)-(10(3y-5))=0



We calculate terms in parentheses: -(10(3y-5)), so:

10(3y-5)

We multiply parentheses

30y-50

Back to the equation:

-(30y-50)



We get rid of parentheses

54y-30y+50=0

We add all the numbers together, and all the variables

24y+50=0

We move all terms containing y to the left, all other terms to the right

24y=-50

y=-50/24

y=-2+1/12

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