5(4d-7)-20(d+5)=d-5(d-9)

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Solution for 5(4d-7)-20(d+5)=d-5(d-9) equation: 



5(4d-7)-20(d+5)=d-5(d-9)

We move all terms to the left:

5(4d-7)-20(d+5)-(d-5(d-9))=0

We multiply parentheses

20d-20d-(d-5(d-9))-35-100=0



We calculate terms in parentheses: -(d-5(d-9)), so:

d-5(d-9)

We multiply parentheses

d-5d+45

We add all the numbers together, and all the variables

-4d+45

Back to the equation:

-(-4d+45)



We add all the numbers together, and all the variables

-(-4d+45)-135=0

We get rid of parentheses

4d-45-135=0

We add all the numbers together, and all the variables

4d-180=0

We move all terms containing d to the left, all other terms to the right

4d=180

d=180/4

d=45

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