2/7*(4m-18)=12

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Solution for 2/7*(4m-18)=12 equation: 



2/7(4m-18)=12

We move all terms to the left:

2/7(4m-18)-(12)=0



Domain of the equation: 7(4m-18)!=0

m∈R



We multiply all the terms by the denominator


-12*7(4m-18)+2=0

Wy multiply elements

-84m(4+2=0

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