27n+10-7(3n-2)=3+7(n+3)

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Solution for 27n+10-7(3n-2)=3+7(n+3) equation: 



27n+10-7(3n-2)=3+7(n+3)

We move all terms to the left:

27n+10-7(3n-2)-(3+7(n+3))=0

We multiply parentheses

27n-21n-(3+7(n+3))+14+10=0



We calculate terms in parentheses: -(3+7(n+3)), so:

3+7(n+3)

determiningTheFunctionDomain
7(n+3)+3

We multiply parentheses

7n+21+3

We add all the numbers together, and all the variables

7n+24

Back to the equation:

-(7n+24)



We add all the numbers together, and all the variables

6n-(7n+24)+24=0

We get rid of parentheses

6n-7n-24+24=0

We add all the numbers together, and all the variables

-n=0

n=0/-1

n=0

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