5(3y-2)-4=17-(4y+5)

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Solution for 5(3y-2)-4=17-(4y+5) equation: 



5(3y-2)-4=17-(4y+5)

We move all terms to the left:

5(3y-2)-4-(17-(4y+5))=0

We multiply parentheses

15y-(17-(4y+5))-10-4=0



We calculate terms in parentheses: -(17-(4y+5)), so:

17-(4y+5)

determiningTheFunctionDomain
-(4y+5)+17

We get rid of parentheses

-4y-5+17

We add all the numbers together, and all the variables

-4y+12

Back to the equation:

-(-4y+12)



We add all the numbers together, and all the variables

15y-(-4y+12)-14=0

We get rid of parentheses

15y+4y-12-14=0

We add all the numbers together, and all the variables

19y-26=0

We move all terms containing y to the left, all other terms to the right

19y=26

y=26/19

y=1+7/19

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