3=4(h-19)+11

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Solution for 3=4(h-19)+11 equation: 



3=4(h-19)+11

We move all terms to the left:

3-(4(h-19)+11)=0



We calculate terms in parentheses: -(4(h-19)+11), so:

4(h-19)+11

We multiply parentheses

4h-76+11

We add all the numbers together, and all the variables

4h-65

Back to the equation:

-(4h-65)



We get rid of parentheses

-4h+65+3=0

We add all the numbers together, and all the variables

-4h+68=0

We move all terms containing h to the left, all other terms to the right

-4h=-68

h=-68/-4

h=+17

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