4a-12=4(a-3)

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Solution for 4a-12=4(a-3) equation: 



4a-12=4(a-3)

We move all terms to the left:

4a-12-(4(a-3))=0



We calculate terms in parentheses: -(4(a-3)), so:

4(a-3)

We multiply parentheses

4a-12

Back to the equation:

-(4a-12)



We get rid of parentheses

4a-4a+12-12=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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