5(3x-8)-5=5(x-4)+45

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Solution for 5(3x-8)-5=5(x-4)+45 equation:



5(3x-8)-5=5(x-4)+45
We move all terms to the left:
5(3x-8)-5-(5(x-4)+45)=0
We multiply parentheses
15x-(5(x-4)+45)-40-5=0
We calculate terms in parentheses: -(5(x-4)+45), so:
5(x-4)+45
We multiply parentheses
5x-20+45
We add all the numbers together, and all the variables
5x+25
Back to the equation:
-(5x+25)
We add all the numbers together, and all the variables
15x-(5x+25)-45=0
We get rid of parentheses
15x-5x-25-45=0
We add all the numbers together, and all the variables
10x-70=0
We move all terms containing x to the left, all other terms to the right
10x=70
x=70/10
x=7

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