-3=12y-5(2y-2)

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Solution for -3=12y-5(2y-2) equation: 



-3=12y-5(2y-2)

We move all terms to the left:

-3-(12y-5(2y-2))=0



We calculate terms in parentheses: -(12y-5(2y-2)), so:

12y-5(2y-2)

We multiply parentheses

12y-10y+10

We add all the numbers together, and all the variables

2y+10

Back to the equation:

-(2y+10)



We get rid of parentheses

-2y-10-3=0

We add all the numbers together, and all the variables

-2y-13=0

We move all terms containing y to the left, all other terms to the right

-2y=13

y=13/-2

y=-6+1/2

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