3u-12=5(u-2)

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Solution for 3u-12=5(u-2) equation: 



3u-12=5(u-2)

We move all terms to the left:

3u-12-(5(u-2))=0



We calculate terms in parentheses: -(5(u-2)), so:

5(u-2)

We multiply parentheses

5u-10

Back to the equation:

-(5u-10)



We get rid of parentheses

3u-5u+10-12=0

We add all the numbers together, and all the variables

-2u-2=0

We move all terms containing u to the left, all other terms to the right

-2u=2

u=2/-2

u=-1

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