5(3x-7)+2(9-2x)=8x-(2x+1)

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Solution for 5(3x-7)+2(9-2x)=8x-(2x+1) equation: 



5(3x-7)+2(9-2x)=8x-(2x+1)

We move all terms to the left:

5(3x-7)+2(9-2x)-(8x-(2x+1))=0

We add all the numbers together, and all the variables

5(3x-7)+2(-2x+9)-(8x-(2x+1))=0

We multiply parentheses

15x-4x-(8x-(2x+1))-35+18=0



We calculate terms in parentheses: -(8x-(2x+1)), so:

8x-(2x+1)

We get rid of parentheses

8x-2x-1

We add all the numbers together, and all the variables

6x-1

Back to the equation:

-(6x-1)



We add all the numbers together, and all the variables

11x-(6x-1)-17=0

We get rid of parentheses

11x-6x+1-17=0

We add all the numbers together, and all the variables

5x-16=0

We move all terms containing x to the left, all other terms to the right

5x=16

x=16/5

x=3+1/5

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