16(3x+2)+13(2x+3)=23(x-12)

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Solution for 16(3x+2)+13(2x+3)=23(x-12) equation: 



16(3x+2)+13(2x+3)=23(x-12)

We move all terms to the left:

16(3x+2)+13(2x+3)-(23(x-12))=0

We multiply parentheses

48x+26x-(23(x-12))+32+39=0



We calculate terms in parentheses: -(23(x-12)), so:

23(x-12)

We multiply parentheses

23x-276

Back to the equation:

-(23x-276)



We add all the numbers together, and all the variables

74x-(23x-276)+71=0

We get rid of parentheses

74x-23x+276+71=0

We add all the numbers together, and all the variables

51x+347=0

We move all terms containing x to the left, all other terms to the right

51x=-347

x=-347/51

x=-6+41/51

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