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10(x+3)+8=2(5x+19)
We move all terms to the left:
10(x+3)+8-(2(5x+19))=0
We multiply parentheses
10x-(2(5x+19))+30+8=0
We calculate terms in parentheses: -(2(5x+19)), so:We add all the numbers together, and all the variables
2(5x+19)
We multiply parentheses
10x+38
Back to the equation:
-(10x+38)
10x-(10x+38)+38=0
We get rid of parentheses
10x-10x-38+38=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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