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5(3x-6)=2(5x+15)
We move all terms to the left:
5(3x-6)-(2(5x+15))=0
We multiply parentheses
15x-(2(5x+15))-30=0
We calculate terms in parentheses: -(2(5x+15)), so:We get rid of parentheses
2(5x+15)
We multiply parentheses
10x+30
Back to the equation:
-(10x+30)
15x-10x-30-30=0
We add all the numbers together, and all the variables
5x-60=0
We move all terms containing x to the left, all other terms to the right
5x=60
x=60/5
x=12
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