(4/3)(x-2)-(1/2)=2(3x/4-1)

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Solution for (4/3)(x-2)-(1/2)=2(3x/4-1) equation: 



(4/3)(x-2)-(1/2)=2(3x/4-1)

We move all terms to the left:

(4/3)(x-2)-(1/2)-(2(3x/4-1))=0



Domain of the equation: 3)(x-2)!=0

x∈R



We add all the numbers together, and all the variables

(+4/3)(x-2)-(2(3x/4-1))-(+1/2)=0

We get rid of parentheses

(+4/3)(x-2)-(2(3x/4-1))-1/2=0

We multiply parentheses ..

(+4x^2+4/3*-2)-(2(3x/4-1))-1/2=0

We calculate fractions


8x^2/()+(-(2(3x*3*-2)*2)/()+()/()=0



We calculate terms in parentheses: +(-(2(3x*3*-2)*2)/()+()/(), so:

-(2(3x*3*-2)*2)/()+()/(

We add all the numbers together, and all the variables

-(2(3x*3*-2)*2)/()+1

We multiply all the terms by the denominator


-(2(3x*3*-2)*2)+1*()



We calculate terms in parentheses: -(2(3x*3*-2)*2), so:

2(3x*3*-2)*2

We multiply parentheses

36x^2-8

Back to the equation:

-(36x^2-8)



We add all the numbers together, and all the variables

-(36x^2-8)

We get rid of parentheses

-36x^2+8

Back to the equation:

+(-36x^2+8)



We get rid of parentheses

8x^2/()-36x^2+8=0

We multiply all the terms by the denominator


8x^2-36x^2*()+8*()=0

We add all the numbers together, and all the variables

8x^2-36x^2*()=0

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