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(4/3)(x-2)-(1/2)=(2)-(3/10)(3x-4)
We move all terms to the left:
(4/3)(x-2)-(1/2)-((2)-(3/10)(3x-4))=0
Domain of the equation: 3)(x-2)!=0
x∈R
Domain of the equation: 10)(3x-4))!=0We add all the numbers together, and all the variables
x∈R
(+4/3)(x-2)-(2-(+3/10)(3x-4))-(+1/2)=0
We get rid of parentheses
(+4/3)(x-2)-(2-(+3/10)(3x-4))-1/2=0
We multiply parentheses ..
(+4x^2+4/3*-2)-(2-(+3/10)(3x-4))-1/2=0
We calculate fractions
((+4x^2+4*10)(3x-4))*2)/(-2)*10)(3x-4))*2+3*)+()/(-2)*10)(3x-4))*2+3*)+(-2)*10)(3x-4))-1*3*)/(-2)*10)(3x-4))*2+3*)=0
We can not solve this equation
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