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3x+8/5x-9=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
3x*5x-9*5x+8=0
Wy multiply elements
15x^2-45x+8=0
a = 15; b = -45; c = +8;
Δ = b2-4ac
Δ = -452-4·15·8
Δ = 1545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{1545}}{2*15}=\frac{45-\sqrt{1545}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{1545}}{2*15}=\frac{45+\sqrt{1545}}{30} $
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