5(3x-5)+8(-4+2x)=6(5x+5)+-6

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Solution for 5(3x-5)+8(-4+2x)=6(5x+5)+-6 equation: 



5(3x-5)+8(-4+2x)=6(5x+5)+-6

We move all terms to the left:

5(3x-5)+8(-4+2x)-(6(5x+5)+-6)=0

We add all the numbers together, and all the variables

5(3x-5)+8(2x-4)-(6(5x+5)+-6)=0

We use the square of the difference formula

5(3x-5)+8(2x-4)-(6(5x+5)-6)=0

We multiply parentheses

15x+16x-(6(5x+5)-6)-25-32=0



We calculate terms in parentheses: -(6(5x+5)-6), so:

6(5x+5)-6

We multiply parentheses

30x+30-6

We add all the numbers together, and all the variables

30x+24

Back to the equation:

-(30x+24)



We add all the numbers together, and all the variables

31x-(30x+24)-57=0

We get rid of parentheses

31x-30x-24-57=0

We add all the numbers together, and all the variables

x-81=0

We move all terms containing x to the left, all other terms to the right

x=81

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