F=9c/5+32c

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Solution for F=9c/5+32c equation:



=9F/5+32F
We move all terms to the left:
-(9F/5+32F)=0
Domain of the equation: 5+32F)!=0
We move all terms containing F to the left, all other terms to the right
32F)!=-5
F!=-5/1
F!=-5
F∈R
We add all the numbers together, and all the variables
-(+32F+9F/5)=0
We get rid of parentheses
-32F-9F/5=0
We multiply all the terms by the denominator
-32F*5-9F=0
We add all the numbers together, and all the variables
-9F-32F*5=0
Wy multiply elements
-9F-160F=0
We add all the numbers together, and all the variables
-169F=0
F=0/-169
F=0

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