5(3x-2)=4(4x-1)

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Solution for 5(3x-2)=4(4x-1) equation: 



5(3x-2)=4(4x-1)

We move all terms to the left:

5(3x-2)-(4(4x-1))=0

We multiply parentheses

15x-(4(4x-1))-10=0



We calculate terms in parentheses: -(4(4x-1)), so:

4(4x-1)

We multiply parentheses

16x-4

Back to the equation:

-(16x-4)



We get rid of parentheses

15x-16x+4-10=0

We add all the numbers together, and all the variables

-1x-6=0

We move all terms containing x to the left, all other terms to the right

-x=6

x=6/-1

x=-6

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