6(2-d)=9(d+4)

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Solution for 6(2-d)=9(d+4) equation: 



6(2-d)=9(d+4)

We move all terms to the left:

6(2-d)-(9(d+4))=0

We add all the numbers together, and all the variables

6(-1d+2)-(9(d+4))=0

We multiply parentheses

-6d-(9(d+4))+12=0



We calculate terms in parentheses: -(9(d+4)), so:

9(d+4)

We multiply parentheses

9d+36

Back to the equation:

-(9d+36)



We get rid of parentheses

-6d-9d-36+12=0

We add all the numbers together, and all the variables

-15d-24=0

We move all terms containing d to the left, all other terms to the right

-15d=24

d=24/-15

d=-1+3/5

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