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(F)=(5-2F/3F-1)
We move all terms to the left:
(F)-((5-2F/3F-1))=0
Domain of the equation: 3F-1))!=0We add all the numbers together, and all the variables
F∈R
F-((-2F/3F+4))=0
We multiply all the terms by the denominator
F*3F-2F+4))-((=0
We add all the numbers together, and all the variables
-2F+F*3F=0
Wy multiply elements
3F^2-2F=0
a = 3; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·3·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*3}=\frac{0}{6} =0 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*3}=\frac{4}{6} =2/3 $
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