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5(3x+4)-2x=7x-7x-3(-2x+11)
We move all terms to the left:
5(3x+4)-2x-(7x-7x-3(-2x+11))=0
We add all the numbers together, and all the variables
-2x+5(3x+4)-(7x-7x-3(-2x+11))=0
We multiply parentheses
-2x+15x-(7x-7x-3(-2x+11))+20=0
We calculate terms in parentheses: -(7x-7x-3(-2x+11)), so:We add all the numbers together, and all the variables
7x-7x-3(-2x+11)
We add all the numbers together, and all the variables
-3(-2x+11)
We multiply parentheses
6x-33
Back to the equation:
-(6x-33)
13x-(6x-33)+20=0
We get rid of parentheses
13x-6x+33+20=0
We add all the numbers together, and all the variables
7x+53=0
We move all terms containing x to the left, all other terms to the right
7x=-53
x=-53/7
x=-7+4/7
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