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3(x-1)+x=+4(x+2)
We move all terms to the left:
3(x-1)+x-(+4(x+2))=0
We add all the numbers together, and all the variables
x+3(x-1)-(+4(x+2))=0
We multiply parentheses
x+3x-(+4(x+2))-3=0
We calculate terms in parentheses: -(+4(x+2)), so:We add all the numbers together, and all the variables
+4(x+2)
determiningTheFunctionDomain 4(x+2)
We multiply parentheses
4x+8
Back to the equation:
-(4x+8)
4x-(4x+8)-3=0
We get rid of parentheses
4x-4x-8-3=0
We add all the numbers together, and all the variables
-11!=0
There is no solution for this equation
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