5(3d-9)-7=5(d-4)+38

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Solution for 5(3d-9)-7=5(d-4)+38 equation: 



5(3d-9)-7=5(d-4)+38

We move all terms to the left:

5(3d-9)-7-(5(d-4)+38)=0

We multiply parentheses

15d-(5(d-4)+38)-45-7=0



We calculate terms in parentheses: -(5(d-4)+38), so:

5(d-4)+38

We multiply parentheses

5d-20+38

We add all the numbers together, and all the variables

5d+18

Back to the equation:

-(5d+18)



We add all the numbers together, and all the variables

15d-(5d+18)-52=0

We get rid of parentheses

15d-5d-18-52=0

We add all the numbers together, and all the variables

10d-70=0

We move all terms containing d to the left, all other terms to the right

10d=70

d=70/10

d=7

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