5(3b-4)=8(b+2)

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Solution for 5(3b-4)=8(b+2) equation: 



5(3b-4)=8(b+2)

We move all terms to the left:

5(3b-4)-(8(b+2))=0

We multiply parentheses

15b-(8(b+2))-20=0



We calculate terms in parentheses: -(8(b+2)), so:

8(b+2)

We multiply parentheses

8b+16

Back to the equation:

-(8b+16)



We get rid of parentheses

15b-8b-16-20=0

We add all the numbers together, and all the variables

7b-36=0

We move all terms containing b to the left, all other terms to the right

7b=36

b=36/7

b=5+1/7

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