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-2(x-5)=6(2-1/2x
We move all terms to the left:
-2(x-5)-(6(2-1/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-2(x-5)-(6(-1/2x+2)=0
We multiply parentheses
-2x-(6(-1/2x+2)+10=0
We multiply all the terms by the denominator
-2x*2x+2)+10-(6(-1=0
We add all the numbers together, and all the variables
-2x*2x=0
Wy multiply elements
-4x^2=0
a = -4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-4)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{-8}=0$
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