4y=2(y+-5)+-2

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Solution for 4y=2(y+-5)+-2 equation:



4y=2(y+-5)+-2
We move all terms to the left:
4y-(2(y+-5)+-2)=0
We add all the numbers together, and all the variables
4y-(2(y-5)+-2)=0
We use the square of the difference formula
4y-(2(y-5)-2)=0
We calculate terms in parentheses: -(2(y-5)-2), so:
2(y-5)-2
We multiply parentheses
2y-10-2
We add all the numbers together, and all the variables
2y-12
Back to the equation:
-(2y-12)
We get rid of parentheses
4y-2y+12=0
We add all the numbers together, and all the variables
2y+12=0
We move all terms containing y to the left, all other terms to the right
2y=-12
y=-12/2
y=-6

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