5(3-2x)=65-2(7-4x)

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Solution for 5(3-2x)=65-2(7-4x) equation: 



5(3-2x)=65-2(7-4x)

We move all terms to the left:

5(3-2x)-(65-2(7-4x))=0

We add all the numbers together, and all the variables

5(-2x+3)-(65-2(-4x+7))=0

We multiply parentheses

-10x-(65-2(-4x+7))+15=0



We calculate terms in parentheses: -(65-2(-4x+7)), so:

65-2(-4x+7)

determiningTheFunctionDomain
-2(-4x+7)+65

We multiply parentheses

8x-14+65

We add all the numbers together, and all the variables

8x+51

Back to the equation:

-(8x+51)



We get rid of parentheses

-10x-8x-51+15=0

We add all the numbers together, and all the variables

-18x-36=0

We move all terms containing x to the left, all other terms to the right

-18x=36

x=36/-18

x=-2

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