5x-4(x-2)=7(3+2x)

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Solution for 5x-4(x-2)=7(3+2x) equation: 



5x-4(x-2)=7(3+2x)

We move all terms to the left:

5x-4(x-2)-(7(3+2x))=0

We add all the numbers together, and all the variables

5x-4(x-2)-(7(2x+3))=0

We multiply parentheses

5x-4x-(7(2x+3))+8=0



We calculate terms in parentheses: -(7(2x+3)), so:

7(2x+3)

We multiply parentheses

14x+21

Back to the equation:

-(14x+21)



We add all the numbers together, and all the variables

x-(14x+21)+8=0

We get rid of parentheses

x-14x-21+8=0

We add all the numbers together, and all the variables

-13x-13=0

We move all terms containing x to the left, all other terms to the right

-13x=13

x=13/-13

x=-1

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