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6(2x-5)=5(4x+2)
We move all terms to the left:
6(2x-5)-(5(4x+2))=0
We multiply parentheses
12x-(5(4x+2))-30=0
We calculate terms in parentheses: -(5(4x+2)), so:We get rid of parentheses
5(4x+2)
We multiply parentheses
20x+10
Back to the equation:
-(20x+10)
12x-20x-10-30=0
We add all the numbers together, and all the variables
-8x-40=0
We move all terms containing x to the left, all other terms to the right
-8x=40
x=40/-8
x=-5
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