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5(2x-9)-5=5(x-3)+10
We move all terms to the left:
5(2x-9)-5-(5(x-3)+10)=0
We multiply parentheses
10x-(5(x-3)+10)-45-5=0
We calculate terms in parentheses: -(5(x-3)+10), so:We add all the numbers together, and all the variables
5(x-3)+10
We multiply parentheses
5x-15+10
We add all the numbers together, and all the variables
5x-5
Back to the equation:
-(5x-5)
10x-(5x-5)-50=0
We get rid of parentheses
10x-5x+5-50=0
We add all the numbers together, and all the variables
5x-45=0
We move all terms containing x to the left, all other terms to the right
5x=45
x=45/5
x=9
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