(6+v)(2v+3)=0

Solution for (6+v)(2v+3)=0 equation:

(6+v)(2v+3)=0

We add all the numbers together, and all the variables

(v+6)(2v+3)=0

We multiply parentheses ..

(+2v^2+3v+12v+18)=0

We get rid of parentheses

2v^2+3v+12v+18=0

We add all the numbers together, and all the variables

2v^2+15v+18=0

a = 2; b = 15; c = +18;
Δ = b2-4ac
Δ = 152-4·2·18
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-9}{2*2}=\frac{-24}{4}
=-6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+9}{2*2}=\frac{-6}{4}
=-1+1/2
$