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2(x-6)+10=2(2x+2)
We move all terms to the left:
2(x-6)+10-(2(2x+2))=0
We multiply parentheses
2x-(2(2x+2))-12+10=0
We calculate terms in parentheses: -(2(2x+2)), so:We add all the numbers together, and all the variables
2(2x+2)
We multiply parentheses
4x+4
Back to the equation:
-(4x+4)
2x-(4x+4)-2=0
We get rid of parentheses
2x-4x-4-2=0
We add all the numbers together, and all the variables
-2x-6=0
We move all terms containing x to the left, all other terms to the right
-2x=6
x=6/-2
x=-3
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