5(2x-7)+4x=7-2(5-3x)

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Solution for 5(2x-7)+4x=7-2(5-3x) equation: 



5(2x-7)+4x=7-2(5-3x)

We move all terms to the left:

5(2x-7)+4x-(7-2(5-3x))=0

We add all the numbers together, and all the variables

5(2x-7)+4x-(7-2(-3x+5))=0

We add all the numbers together, and all the variables

4x+5(2x-7)-(7-2(-3x+5))=0

We multiply parentheses

4x+10x-(7-2(-3x+5))-35=0



We calculate terms in parentheses: -(7-2(-3x+5)), so:

7-2(-3x+5)

determiningTheFunctionDomain
-2(-3x+5)+7

We multiply parentheses

6x-10+7

We add all the numbers together, and all the variables

6x-3

Back to the equation:

-(6x-3)



We add all the numbers together, and all the variables

14x-(6x-3)-35=0

We get rid of parentheses

14x-6x+3-35=0

We add all the numbers together, and all the variables

8x-32=0

We move all terms containing x to the left, all other terms to the right

8x=32

x=32/8

x=4

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