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(x/7)11x=7
We move all terms to the left:
(x/7)11x-(7)=0
Domain of the equation: 7)11x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+x/7)11x-7=0
We multiply parentheses
11x^2-7=0
a = 11; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·11·(-7)
Δ = 308
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{308}=\sqrt{4*77}=\sqrt{4}*\sqrt{77}=2\sqrt{77}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{77}}{2*11}=\frac{0-2\sqrt{77}}{22} =-\frac{2\sqrt{77}}{22} =-\frac{\sqrt{77}}{11} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{77}}{2*11}=\frac{0+2\sqrt{77}}{22} =\frac{2\sqrt{77}}{22} =\frac{\sqrt{77}}{11} $
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