(x-2)-(x+x)=10-(3-x)

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Solution for (x-2)-(x+x)=10-(3-x) equation: 



(x-2)-(x+x)=10-(3-x)

We move all terms to the left:

(x-2)-(x+x)-(10-(3-x))=0

We add all the numbers together, and all the variables

(x-2)-(+2x)-(10-(-1x+3))=0

We get rid of parentheses

x-2x-(10-(-1x+3))-2=0



We calculate terms in parentheses: -(10-(-1x+3)), so:

10-(-1x+3)

determiningTheFunctionDomain
-(-1x+3)+10

We get rid of parentheses

1x-3+10

We add all the numbers together, and all the variables

x+7

Back to the equation:

-(x+7)



We add all the numbers together, and all the variables

-1x-(x+7)-2=0

We get rid of parentheses

-1x-x-7-2=0

We add all the numbers together, and all the variables

-2x-9=0

We move all terms containing x to the left, all other terms to the right

-2x=9

x=9/-2

x=-4+1/2

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