5(2x-4+3x)=5(2x+-4+3x)=10x+20+25x=10x+25x+

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Solution for 5(2x-4+3x)=5(2x+-4+3x)=10x+20+25x=10x+25x+ equation: 



5(2x-4+3x)=5(2x+-4+3x)=10x+20+25x=10x+25x+

We move all terms to the left:

5(2x-4+3x)-(5(2x+-4+3x))=0

We add all the numbers together, and all the variables

5(5x-4)-(5(5x-4))=0

We multiply parentheses

25x-(5(5x-4))-20=0



We calculate terms in parentheses: -(5(5x-4)), so:

5(5x-4)

We multiply parentheses

25x-20

Back to the equation:

-(25x-20)



We get rid of parentheses

25x-25x+20-20=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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