0921=4+n2

Solution for 0921=4+n2 equation:

0921=4+n2

We move all terms to the left:

0921-(4+n2)=0

We add all the numbers together, and all the variables

-(+n^2+4)+0921=0

We add all the numbers together, and all the variables

-(+n^2+4)+921=0

We get rid of parentheses

-n^2-4+921=0

We add all the numbers together, and all the variables

-1n^2+917=0

a = -1; b = 0; c = +917;
Δ = b2-4ac
Δ = 02-4·(-1)·917
Δ = 3668
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3668}=\sqrt{4*917}=\sqrt{4}*\sqrt{917}=2\sqrt{917}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{917}}{2*-1}=\frac{0-2\sqrt{917}}{-2}
=-\frac{2\sqrt{917}}{-2}
=-\frac{\sqrt{917}}{-1}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{917}}{2*-1}=\frac{0+2\sqrt{917}}{-2}
=\frac{2\sqrt{917}}{-2}
=\frac{\sqrt{917}}{-1}
$