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5(2x-4+3x)=5(2x+-4+3x)=10x+
We move all terms to the left:
5(2x-4+3x)-(5(2x+-4+3x))=0
We add all the numbers together, and all the variables
5(5x-4)-(5(5x-4))=0
We multiply parentheses
25x-(5(5x-4))-20=0
We calculate terms in parentheses: -(5(5x-4)), so:We get rid of parentheses
5(5x-4)
We multiply parentheses
25x-20
Back to the equation:
-(25x-20)
25x-25x+20-20=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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