4(2j-3)-(2j-8)=18

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Solution for 4(2j-3)-(2j-8)=18 equation: 



4(2j-3)-(2j-8)=18

We move all terms to the left:

4(2j-3)-(2j-8)-(18)=0

We multiply parentheses

8j-(2j-8)-12-18=0

We get rid of parentheses

8j-2j+8-12-18=0

We add all the numbers together, and all the variables

6j-22=0

We move all terms containing j to the left, all other terms to the right

6j=22

j=22/6

j=3+2/3

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